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Re: RSA != RSA?

To: "Henry Spencer" <henry@spsystems.net>, "IP Security List" <ipsec@lists.tislabs.com>
Subject: Re: RSA != RSA?
From: "Steve Wang" <steve.wang@entegrity.com>
Date: Thu, 8 Feb 2001 14:00:41 -0500
Organization: Entegrity Solutions
References: <Pine.BSI.3.91.1010208094118.1853D-100000@spsystems.net>
Reply-To: "Steve Wang" <steve.wang@entegrity.com>
Sender: owner-ipsec@lists.tislabs.com

> The problem naturally is not visible when exchanging *public* keys, since
> d is found only in the private key.  It becomes an issue only when a key
> *pair* is being generated on one system for use by another, and the
> receiving system is being cautious and checking the key for consistency.
It depends on how the consistency checking goes. If one just chooses
a random message, m, compute c = m^e  mod n, m'=c^d mod n,
and compare m = m' mod n, then the checking will pass.

If one chooses to compute de = 1 mod **, then it may fail.

Steve

References:

RSA != RSA?

From: Henry Spencer <henry@spsystems.net>

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